Area-velocity relation: Difference between revisions

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=== The Area-Velocity Relation ===
=== The Area-Velocity Relation ===


Starting point - the continuity equation (Eqn. \ref{eq:governing:cont}):
Starting point - the continuity equation (Eqn. \ref{eq:governing:cont}):


<math display="block">
{{NumEqn|<math>
d(\rho uA)=0 \Rightarrow \rho u dA+\rho Adu +uAd\rho=0
d(\rho uA)=0 \Rightarrow \rho u dA+\rho Adu +uAd\rho=0
</math>
</math>}}


divide by <math>\rho uA</math> gives
divide by <math>\rho uA</math> gives


<math display="block">
{{NumEqn|<math>
\frac{d\rho}{\rho}+\frac{du}{u}+\frac{dA}{A}=0
\frac{d\rho}{\rho}+\frac{du}{u}+\frac{dA}{A}=0
</math>
</math>}}


As the name suggests, the area-velocity relation is a relation including the area and the flow velocity. Therefore, the next step is to replace the density terms.
As the name suggests, the area-velocity relation is a relation including the area and the flow velocity. Therefore, the next step is to replace the density terms.
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This can be achieved using the momentum equation (Eqn. \ref{eq:governing:mom})
This can be achieved using the momentum equation (Eqn. \ref{eq:governing:mom})


<math display="block">
{{NumEqn|<math>
dp=-\rho udu\Leftrightarrow \frac{dp}{\rho}=-udu
dp=-\rho udu\Leftrightarrow \frac{dp}{\rho}=-udu
</math>
</math>}}


<math display="block">
{{NumEqn|<math>
\frac{dp}{\rho}=\frac{dp}{d\rho}\frac{d\rho}{\rho}=-udu
\frac{dp}{\rho}=\frac{dp}{d\rho}\frac{d\rho}{\rho}=-udu
</math>
</math>}}


If we assume adiabatic and reversible flow processes, i.e., isentropic flow
If we assume adiabatic and reversible flow processes, i.e., isentropic flow


<math display="block">
{{NumEqn|<math>
\frac{dp}{d\rho}=\left(\frac{dp}{d\rho}\right)_s=a^2\Rightarrow a^2\frac{d\rho}{\rho}=-udu
\frac{dp}{d\rho}=\left(\frac{dp}{d\rho}\right)_s=a^2\Rightarrow a^2\frac{d\rho}{\rho}=-udu
</math>
</math>}}


<math display="block">
{{NumEqn|<math>
a^2\frac{d\rho}{\rho}=-udu=-u^2\frac{du}{u}
a^2\frac{d\rho}{\rho}=-udu=-u^2\frac{du}{u}
</math>
</math>}}


<math display="block">
{{NumEqn|<math>
\frac{d\rho}{\rho}=-M^2\frac{du}{u}
\frac{d\rho}{\rho}=-M^2\frac{du}{u}
</math>
</math>}}


Eqn. \ref{eq:governing:mom:b} inserted in Eqn. \ref{eq:governing:cont:b} gives
Eqn. \ref{eq:governing:mom:b} inserted in Eqn. \ref{eq:governing:cont:b} gives


<math display="block">
{{NumEqn|<math>
-M^2\frac{du}{u}+\frac{du}{u}+\frac{dA}{A}=0
-M^2\frac{du}{u}+\frac{du}{u}+\frac{dA}{A}=0
</math>
</math>}}


or
or


<math display="block">
{{NumEqn|<math>
\frac{dA}{A}=(M^2-1)\frac{du}{u}
\frac{dA}{A}=(M^2-1)\frac{du}{u}
</math>
</math>}}


which is the area-velocity relation.
which is the area-velocity relation.