Crocco's equation: Difference between revisions

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The momentum equation without body forces
The momentum equation without body forces


<math display="block">
{{NumEqn|<math>
\rho\frac{D\mathbf{v}}{Dt}=-\nabla p
\rho\frac{D\mathbf{v}}{Dt}=-\nabla p
</math>
</math>}}


Expanding the substantial derivative
Expanding the substantial derivative


<math display="block">
{{NumEqn|<math>
\rho\frac{\partial \mathbf{v}}{\partial t}+\rho\mathbf{v}\cdot\nabla\mathbf{v}=-\nabla p
\rho\frac{\partial \mathbf{v}}{\partial t}+\rho\mathbf{v}\cdot\nabla\mathbf{v}=-\nabla p
</math>
</math>}}


The first and second law of thermodynamics gives
The first and second law of thermodynamics gives


<math display="block">
{{NumEqn|<math>
T\nabla s =\nabla h-\frac{\nabla p}{\rho}
T\nabla s =\nabla h-\frac{\nabla p}{\rho}
</math>
</math>}}


Insert <math>\nabla p</math> from the momentum equation
Insert <math>\nabla p</math> from the momentum equation


<math display="block">
{{NumEqn|<math>
T\nabla s =\nabla h+\frac{\partial \mathbf{v}}{\partial t}+\mathbf{v}\cdot\nabla\mathbf{v}
T\nabla s =\nabla h+\frac{\partial \mathbf{v}}{\partial t}+\mathbf{v}\cdot\nabla\mathbf{v}
</math>
</math>}}


Definition of total enthalpy (<math>h_o</math>)
Definition of total enthalpy (<math>h_o</math>)


<math display="block">
{{NumEqn|<math>
h_o=h+\frac{1}{2}\mathbf{v}\cdot\mathbf{v}\Rightarrow \nabla h=\nabla h_o-\nabla\left(\frac{1}{2}\mathbf{v}\cdot\mathbf{v}\right)
h_o=h+\frac{1}{2}\mathbf{v}\cdot\mathbf{v}\Rightarrow \nabla h=\nabla h_o-\nabla\left(\frac{1}{2}\mathbf{v}\cdot\mathbf{v}\right)
</math>
</math>}}


The last term can be rewritten as
The last term can be rewritten as


<math display="block">
{{NumEqn|<math>
\nabla\left(\frac{1}{2}\mathbf{v}\cdot\mathbf{v}\right)=\mathbf{v}\times(\nabla\times\mathbf{v})+\mathbf{v}\cdot\nabla\mathbf{v}
\nabla\left(\frac{1}{2}\mathbf{v}\cdot\mathbf{v}\right)=\mathbf{v}\times(\nabla\times\mathbf{v})+\mathbf{v}\cdot\nabla\mathbf{v}
</math>
</math>}}


which gives
which gives


<math display="block">
{{NumEqn|<math>
\nabla h=\nabla h_o-\mathbf{v}\times(\nabla\times\mathbf{v})-\mathbf{v}\cdot\nabla\mathbf{v}
\nabla h=\nabla h_o-\mathbf{v}\times(\nabla\times\mathbf{v})-\mathbf{v}\cdot\nabla\mathbf{v}
</math>
</math>}}


Insert <math>\nabla h</math> in the entropy equation gives
Insert <math>\nabla h</math> in the entropy equation gives


<math display="block">
{{NumEqn|<math>
T\nabla s =\nabla h_o-\mathbf{v}\times(\nabla\times\mathbf{v})-\cancel{\mathbf{v}\cdot\nabla\mathbf{v}}+\frac{\partial \mathbf{v}}{\partial t}+\cancel{\mathbf{v}\cdot\nabla\mathbf{v}}
T\nabla s =\nabla h_o-\mathbf{v}\times(\nabla\times\mathbf{v})-\cancel{\mathbf{v}\cdot\nabla\mathbf{v}}+\frac{\partial \mathbf{v}}{\partial t}+\cancel{\mathbf{v}\cdot\nabla\mathbf{v}}
</math>
</math>}}


<math display="block">
{{NumEqn|<math>
T\nabla s =\nabla h_o-\mathbf{v}\times(\nabla\times\mathbf{v})+\frac{\partial \mathbf{v}}{\partial t}
T\nabla s =\nabla h_o-\mathbf{v}\times(\nabla\times\mathbf{v})+\frac{\partial \mathbf{v}}{\partial t}
</math>
</math>}}