The entropy equation: Difference between revisions

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From the second law of thermodynamics
From the second law of thermodynamics


<math display="block">
{{NumEqn|<math>
\frac{De}{Dt}=T\frac{Ds}{Dt}-p\frac{D}{Dt}\left(\frac{1}{\rho}\right)
\frac{De}{Dt}=T\frac{Ds}{Dt}-p\frac{D}{Dt}\left(\frac{1}{\rho}\right)
</math>
</math>}}


From the energy equation on differential non-conservation form internal energy formulation
From the energy equation on differential non-conservation form internal energy formulation


<math display="block">
{{NumEqn|<math>
\frac{De}{Dt} = \dot{q} - \frac{p}{\rho}(\nabla\cdot\mathbf{v})
\frac{De}{Dt} = \dot{q} - \frac{p}{\rho}(\nabla\cdot\mathbf{v})
</math>
</math>}}


The continuity equation on differential non-conservation form
The continuity equation on differential non-conservation form


<math display="block">
{{NumEqn|<math>
\frac{D\rho}{Dt}+\rho(\nabla\cdot\mathbf{v})=0 \Rightarrow \nabla\cdot\mathbf{v}=-\frac{1}{\rho}\frac{D\rho}{Dt}
\frac{D\rho}{Dt}+\rho(\nabla\cdot\mathbf{v})=0 \Rightarrow \nabla\cdot\mathbf{v}=-\frac{1}{\rho}\frac{D\rho}{Dt}
</math>
</math>}}


and thus
and thus


<math display="block">
{{NumEqn|<math>
\frac{De}{Dt} = \dot{q} +\frac{p}{\rho^2}\frac{D\rho}{Dt}
\frac{De}{Dt} = \dot{q} +\frac{p}{\rho^2}\frac{D\rho}{Dt}
</math>
</math>}}


<math display="block">
{{NumEqn|<math>
\frac{D\rho}{Dt}=-\frac{1}{\nu^2}\frac{D\nu}{Dt}
\frac{D\rho}{Dt}=-\frac{1}{\nu^2}\frac{D\nu}{Dt}
</math>
</math>}}


<math display="block">
{{NumEqn|<math>
\rho\frac{De}{Dt} = \rho\dot{q} -\frac{p}{\rho\nu^2}\frac{D\nu}{Dt} = \rho\dot{q} -\rho p\frac{D\nu}{Dt}
\rho\frac{De}{Dt} = \rho\dot{q} -\frac{p}{\rho\nu^2}\frac{D\nu}{Dt} = \rho\dot{q} -\rho p\frac{D\nu}{Dt}
</math>
</math>}}


<math display="block">
{{NumEqn|<math>
\rho\left[\frac{De}{Dt}+p\frac{D\nu}{Dt}-\dot{q}\right]=0\Rightarrow\frac{De}{Dt}=\dot{q}-p\frac{D\nu}{Dt}
\rho\left[\frac{De}{Dt}+p\frac{D\nu}{Dt}-\dot{q}\right]=0\Rightarrow\frac{De}{Dt}=\dot{q}-p\frac{D\nu}{Dt}
</math>
</math>}}


Insert <math>De/Dt</math> in Eqn. \ref{eq:second:law}
Insert <math>De/Dt</math> in Eqn. \ref{eq:second:law}


<math display="block">
{{NumEqn|<math>
\dot{q}-p\frac{D}{Dt}\left(\frac{1}{\rho}\right)=T\frac{Ds}{Dt}-p\frac{D}{Dt}\left(\frac{1}{\rho}\right)\Rightarrow
\dot{q}-p\frac{D}{Dt}\left(\frac{1}{\rho}\right)=T\frac{Ds}{Dt}-p\frac{D}{Dt}\left(\frac{1}{\rho}\right)\Rightarrow
</math>
</math>}}


<math display="block">
{{NumEqn|<math>
T\frac{Ds}{Dt}=-\dot{q}
T\frac{Ds}{Dt}=-\dot{q}
</math>
</math>}}


Adiabatic flow:
Adiabatic flow:


<math display="block">
{{NumEqn|<math>
T\frac{Ds}{Dt}=0
T\frac{Ds}{Dt}=0
</math>
</math>}}


In an adiabatic, steady-state, inviscid flow, entropy is constant along a streamline.
In an adiabatic, steady-state, inviscid flow, entropy is constant along a streamline.