Isentropic relations: Difference between revisions

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{{NumEqn|<math>
{{NumEqn|<math>
de=Tds-pd\left(\frac{1}{\rho}\right)
de=Tds-pd\left(\frac{1}{\rho}\right)
</math>|2}}
</math>|eq-first-law-b|2}}


Enthalpy is defined as: <math>h=e+p/\rho</math> and thus
Enthalpy is defined as: <math>h=e+p/\rho</math> and thus
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{{NumEqn|<math>
{{NumEqn|<math>
dh=de+pd\left(\frac{1}{\rho}\right)+\left(\frac{1}{\rho}\right)dp
dh=de+pd\left(\frac{1}{\rho}\right)+\left(\frac{1}{\rho}\right)dp
</math>|3}}
</math>|eq-dh|3}}


Eliminate $de$ in Eqn. \ref{eq:firstlaw:b} using Eqn. \ref{eq:dh}
Eliminate <math>de</math> in {{EquationNote|eq-first-law-b}} using {{EquationNote|eq-dh}}


{{NumEqn|<math>
{{NumEqn|<math>