Isentropic relations: Difference between revisions

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{{NumEqn|<math>
{{NumEqn|<math>
de=Tds-pd\left(\frac{1}{\rho}\right)
de=Tds-pd\left(\frac{1}{\rho}\right)
</math>|eq-first-law-b}}
</math>|label=eq-first-law-b}}


Enthalpy is defined as: <math>h=e+p/\rho</math> and thus
Enthalpy is defined as: <math>h=e+p/\rho</math> and thus
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{{NumEqn|<math>
{{NumEqn|<math>
dh=de+pd\left(\frac{1}{\rho}\right)+\left(\frac{1}{\rho}\right)dp
dh=de+pd\left(\frac{1}{\rho}\right)+\left(\frac{1}{\rho}\right)dp
</math>|eq-dh}}
</math>|label=eq-dh}}


Eliminate <math>de</math> in {{EquationNote|eq-first-law-b}} using {{EquationNote|eq-dh}}
Eliminate <math>de</math> in {{EquationNote|label=eq-first-law-b}} using {{EquationNote|label=eq-dh}}


{{NumEqn|<math>
{{NumEqn|<math>
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{{NumEqn|<math>
{{NumEqn|<math>
ds=C_p\frac{dT}{T}-R\frac{dp}{p}
ds=C_p\frac{dT}{T}-R\frac{dp}{p}
</math>|eq-ds}}
</math>|label=eq-ds}}


Integrating {{EquationNote|eq-ds}} gives
Integrating {{EquationNote|eq-ds}} gives
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{{NumEqn|<math>
{{NumEqn|<math>
s_2-s_1=\int_1^2 C_p\frac{dT}{T}-R\ln\left(\frac{p_2}{p_1}\right)
s_2-s_1=\int_1^2 C_p\frac{dT}{T}-R\ln\left(\frac{p_2}{p_1}\right)
</math>|eq-ds-b}}
</math>|label=eq-ds-b}}


For a calorically perfect gas, <math>C_p</math> is constant (not a function of temperature) and can be moved out from the integral and thus
For a calorically perfect gas, <math>C_p</math> is constant (not a function of temperature) and can be moved out from the integral and thus
Line 54: Line 54:
{{NumEqn|<math>
{{NumEqn|<math>
s_2-s_1=C_p\ln\left(\frac{T_2}{T_1}\right)-R\ln\left(\frac{p_2}{p_1}\right)
s_2-s_1=C_p\ln\left(\frac{T_2}{T_1}\right)-R\ln\left(\frac{p_2}{p_1}\right)
</math>|eq-ds-c}}
</math>|label=eq-ds-c}}


An alternative form of {{EquationNote|eq-ds-c}} is obtained by using <math>de=C_v dT</math> in {{EquationNote|eq-first-law-b}}, which gives
An alternative form of {{EquationNote|label=eq-ds-c}} is obtained by using <math>de=C_v dT</math> in {{EquationNote|label=eq-first-law-b}}, which gives


{{NumEqn|<math>
{{NumEqn|<math>
s_2-s_1=\int_1^2 C_v\frac{dT}{T}-R\ln\left(\frac{\rho_2}{\rho_1}\right)
s_2-s_1=\int_1^2 C_v\frac{dT}{T}-R\ln\left(\frac{\rho_2}{\rho_1}\right)
</math>|eq-ds-d}}
</math>|label=eq-ds-d}}


Again, for a calorically perfect gas, we get
Again, for a calorically perfect gas, we get
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{{NumEqn|<math>
{{NumEqn|<math>
s_2-s_1=C_v\ln\left(\frac{T_2}{T_1}\right)-R\ln\left(\frac{\rho_2}{\rho_1}\right)
s_2-s_1=C_v\ln\left(\frac{T_2}{T_1}\right)-R\ln\left(\frac{\rho_2}{\rho_1}\right)
</math>|eq-ds-e}}
</math>|label=eq-ds-e}}


=== Isentropic Relations ===
=== Isentropic Relations ===


Adiabatic and reversible processes, i.e., isentropic processes implies <math>ds=0</math> and thus {{EquationNote|eq-ds-c}} reduces to
Adiabatic and reversible processes, i.e., isentropic processes implies <math>ds=0</math> and thus {{EquationNote|label=eq-ds-c}} reduces to


{{NumEqn|<math>
{{NumEqn|<math>
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{{NumEqn|<math>
{{NumEqn|<math>
\frac{p_2}{p_1}=\left(\frac{T_2}{T_1}\right)^{\gamma/(\gamma-1)}
\frac{p_2}{p_1}=\left(\frac{T_2}{T_1}\right)^{\gamma/(\gamma-1)}
</math>|eq-isentropic-a}}
</math>|label=eq-isentropic-a}}


In the same way, {{EquationNote|eq-ds-e}} gives
In the same way, {{EquationNote|label=eq-ds-e}} gives


{{NumEqn|<math>
{{NumEqn|<math>
\frac{\rho_2}{\rho_1}=\left(\frac{T_2}{T_1}\right)^{1/(\gamma-1)}
\frac{\rho_2}{\rho_1}=\left(\frac{T_2}{T_1}\right)^{1/(\gamma-1)}
</math>|eq-isentropic-b}}
</math>|label=eq-isentropic-b}}