Thermodynamic processes: Difference between revisions

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=== Specific Heat Relations ===
For thermally perfect and calorically perfect gases
<math display="block">
\begin{aligned}
&C_p=\frac{dh}{dT}\\
&C_v=\frac{de}{dT}
\end{aligned}
</math>
From the definition of enthalpy and the equation of state <math>p=\rho RT</math>
<math display="block">
h=e+\frac{p}{\rho}=e+RT
</math>
Differentiate Eqn. \ref{eq:enthalpy} with respect to temperature gives
<math display="block">
\frac{dh}{dT}=\frac{de}{dT}+\frac{d(RT)}{dT}
</math>
Inserting the specific heats gives
<math display="block">
C_p=C_v+R
</math>
Dividing Eqn. \ref{eq:specificheat:b} by <math>C_v</math> gives
<math display="block">
\frac{C_p}{C_v}=1+\frac{R}{C_v}
</math>
Introducing the ratio of specific heats defined as
<math display="block">
\gamma=\frac{C_p}{C_v}
</math>
Now, inserting Eqn. \ref{eq:gamma} in Eqn. \ref{eq:specificheat:c} gives
<math display="block">
C_v=\frac{R}{\gamma-1}
</math>
In the same way, dividing Eqn. \ref{eq:specificheat:b} with <math>C_p</math> gives
<math display="block">
1=\frac{C_v}{C_p}+\frac{R}{C_p}=\frac{1}{\gamma}+\frac{R}{C_p}
</math>
and thus
<math display="block">
C_p=\frac{\gamma R}{\gamma-1}
</math>
=== Isentropic Relations ===
First law of thermodynamics:
<math display="block">
de=\delta q - \delta w
</math>
For a reversible process: <math>\delta w=pd(1/\rho)</math> and <math>\delta q=Tds</math>
<math display="block">
de=Tds-pd\left(\frac{1}{\rho}\right)
</math>
Enthalpy is defined as: <math>h=e+p/\rho</math> and thus
<math display="block">
dh=de+pd\left(\frac{1}{\rho}\right)+\left(\frac{1}{\rho}\right)dp
</math>
Eliminate $de$ in Eqn. \ref{eq:firstlaw:b} using Eqn. \ref{eq:dh}
<math display="block">
Tds=dh-\cancel{pd\left(\frac{1}{\rho}\right)}-\left(\frac{1}{\rho}\right)dp+\cancel{pd\left(\frac{1}{\rho}\right)}
</math>
<math display="block">
ds=\frac{dh}{T}-\frac{dp}{\rho T}
</math>
Using <math>dh=C_p T</math> and the equation of state <math>p=\rho RT</math>, we get
<math display="block">
ds=C_p\frac{dT}{T}-R\frac{dp}{p}
</math>
Integrating Eqn. \ref{eq:ds} gives
<math display="block">
s_2-s_1=\int_1^2 C_p\frac{dT}{T}-R\ln\left(\frac{p_2}{p_1}\right)
</math>
For a calorically perfect gas, <math>C_p</math> is constant (not a function of temperature) and can be moved out from the integral and thus
<math display="block">
s_2-s_1=C_p\ln\left(\frac{T_2}{T_1}\right)-R\ln\left(\frac{p_2}{p_1}\right)
</math>
An alternative form of Eqn. \ref{eq:ds:c} is obtained by using <math>de=C_v dT</math> Eqn. \ref{eq:firstlaw:b}, which gives
<math display="block">
s_2-s_1=\int_1^2 C_v\frac{dT}{T}-R\ln\left(\frac{\rho_2}{\rho_1}\right)
</math>
Again, for a calorically perfect gas, we get
<math display="block">
s_2-s_1=C_v\ln\left(\frac{T_2}{T_1}\right)-R\ln\left(\frac{\rho_2}{\rho_1}\right)
</math>
=== Isentropic Relations ===
Adiabatic and reversible processes, i.e., isentropic processes implies <math>ds=0</math> and thus Eqn. \ref{eq:ds:c} reduces to
<math display="block">
\frac{C_p}{R}\ln\left(\frac{T_2}{T_1}\right)=\ln\left(\frac{p_2}{p_1}\right)
</math>
<math display="block">
\frac{C_p}{R}=\frac{\gamma}{\gamma-1}
</math>
<math display="block">
\frac{\gamma}{\gamma-1}\ln\left(\frac{T_2}{T_1}\right)=\ln\left(\frac{p_2}{p_1}\right)\Rightarrow
</math>
<math display="block">
\frac{p_2}{p_1}=\left(\frac{T_2}{T_1}\right)^{\gamma/(\gamma-1)}
</math>
In the same way, Eqn. \ref{eq:ds:e} gives
<math display="block">
\frac{\rho_2}{\rho_1}=\left(\frac{T_2}{T_1}\right)^{1/(\gamma-1)}
</math>
Eqn. \ref{eq:isentropic:a} and Eqn. \ref{eq:isentropic:b} constitutes the isentropic relations
<math display="block">
\frac{p_2}{p_1}=\left(\frac{\rho_2}{\rho_1}\right)^{\gamma}=\left(\frac{T_2}{T_1}\right)^{\gamma/(\gamma-1)}
</math>
=== Flow Processes ===


<math display="block">
<math display="block">

Revision as of 22:12, 16 March 2026


ds=CvdTT+Rdνν

dν=νRdsCvνRTdT=νRdsCvpdT

for an isentropic process (ds=0), dν<0 for positive values of dT.

ds=CpdTTRdpp

dp=pRds+CppRTdT=pRds+CpρdT

for an isentropic process (ds=0), dp>0 for positive values of dT.


Since ν decreases with temperature and pressure increases with temperature for an isentropic process, we can see from Eqn.~\ref{eqn:process:dnu} that dν will be greater at lower temperatures and thus isochores (lines of constant specific volume) will be closely spaced at low temperatures and more sparse at higher temperatures. For an isochore dv=0 which implies

0=νR(dsCvdTT)dTds=TCv

and thus we can see that the slope of an isochore in a Ts-diagram is positive and that the slope increases with temperature.

In analogy, we can see that an isobar (dp=0) leads to the following relation

0=pR(CpdTTds)dTds=TCp

and consequently isobars will also have a positive slope that increases with temperature in a Ts-diagram. Moreover, isobars are less steep than ischores as Cp>Cv.