Governing equations on differential form: Difference between revisions

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{{NumEqn|<math>
{{NumEqn|<math>
\frac{\partial \rho}{\partial t} + \nabla\cdot(\rho\mathbf{v})=0
\frac{\partial \rho}{\partial t} + \nabla\cdot(\rho\mathbf{v})=0
</math>}}
</math>|label=eq-cont-pde}}


which is the continuity equation on partial differential form.
which is the continuity equation on partial differential form.
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{{NumEqn|<math>
{{NumEqn|<math>
\frac{\partial}{\partial t}(\rho \mathbf{v}) + \nabla\cdot(\rho \mathbf{v}\mathbf{v}) + \nabla p = \rho \mathbf{f}  
\frac{\partial}{\partial t}(\rho \mathbf{v}) + \nabla\cdot(\rho \mathbf{v}\mathbf{v}) + \nabla p = \rho \mathbf{f}  
</math>}}
</math>|label=eq-mom-pde}}


which is the momentum equation on partial differential form
which is the momentum equation on partial differential form
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{{NumEqn|<math>
{{NumEqn|<math>
\frac{\partial}{\partial t}(\rho e_o) + \nabla\cdot(\rho h_o\mathbf{v}) = \rho\mathbf{f}\cdot\mathbf{v} + \dot{q}\rho
\frac{\partial}{\partial t}(\rho e_o) + \nabla\cdot(\rho h_o\mathbf{v}) = \rho\mathbf{f}\cdot\mathbf{v} + \dot{q}\rho
</math>}}
</math>|label=eq-energy-pde}}


which is the energy equation on partial differential form
which is the energy equation on partial differential form
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{{NumEqn|<math>
{{NumEqn|<math>
\frac{D}{Dt}=\frac{\partial}{\partial t}+\mathbf{v}\cdot\nabla
\frac{D}{Dt}=\frac{\partial}{\partial t}+\mathbf{v}\cdot\nabla
</math>}}
</math>|label=eq-cont-pde-non-cons}}


where the first term of the right hand side is the local derivative and the second term is the convective derivative.
where the first term of the right hand side is the local derivative and the second term is the convective derivative.
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{{NumEqn|<math>
{{NumEqn|<math>
\frac{D\mathbf{v}}{Dt}+\frac{1}{\rho}\nabla p = \mathbf{f}
\frac{D\mathbf{v}}{Dt}+\frac{1}{\rho}\nabla p = \mathbf{f}
</math>}}
</math>|label=eq-mom-pde-non-cons}}


==== Conservation of Energy ====
==== Conservation of Energy ====


The last equation on non-conservation differential form is the energy equation. We start by rewriting the energy equation on differential form (Eqn. \ref{eq:governing:energy:pde}), repeated here for convenience
The last equation on non-conservation differential form is the energy equation. We start by rewriting the energy equation on differential form {{EquationNote|label=eq-energy-pde}}, repeated here for convenience


{{NumEqn|<math>
{{NumEqn|<math>
\frac{\partial}{\partial t}(\rho e_o) + \nabla\cdot(\rho h_o\mathbf{v}) = \rho\mathbf{f}\cdot\mathbf{v} + \dot{q}\rho
\frac{\partial}{\partial t}(\rho e_o) + \nabla\cdot(\rho h_o\mathbf{v}) = \rho\mathbf{f}\cdot\mathbf{v} + \dot{q}\rho
</math>}}
</math>|nonumber=1}}


Total enthalpy, <math>h_o</math>, is replaced with total energy, <math>e_o</math>
Total enthalpy, <math>h_o</math>, is replaced with total energy, <math>e_o</math>
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{{NumEqn|<math>
{{NumEqn|<math>
\rho\frac{\partial e_o}{\partial t} + e_o\frac{\partial \rho}{\partial t} + \rho\mathbf{v}\cdot\nabla e_o + e_o\nabla\cdot(\rho \mathbf{v}) + \nabla\cdot(p\mathbf{v})= \rho\mathbf{f}\cdot\mathbf{v} + \dot{q}\rho
\rho\frac{\partial e_o}{\partial t} + e_o\frac{\partial \rho}{\partial t} + \rho\mathbf{v}\cdot\nabla e_o + e_o\nabla\cdot(\rho \mathbf{v}) + \nabla\cdot(p\mathbf{v})=</math><br><br><math>= \rho\mathbf{f}\cdot\mathbf{v} + \dot{q}\rho
</math>}}
</math>}}


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{{NumEqn|<math>
{{NumEqn|<math>
\rho\frac{De_o}{Dt} + \nabla\cdot(p\mathbf{v}) = \rho\mathbf{f}\cdot\mathbf{v} + \dot{q}\rho
\rho\frac{De_o}{Dt} + \nabla\cdot(p\mathbf{v}) = \rho\mathbf{f}\cdot\mathbf{v} + \dot{q}\rho
</math>}}
</math>|label=eq-energy-pde-non-cons}}


==== Summary ====
==== Summary ====
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</math>}}
</math>}}


Inserted in Eqn. \ref{eq:governing:energy:non}, this gives
Inserted in {{EquationNote|label=eq-energy-pde-non-cons|nopar=1}}, this gives


{{NumEqn|<math>
{{NumEqn|<math>
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</math>}}
</math>}}


Now, let's replace the substantial derivative <math>D\mathbf{v}/Dt</math> using the momentum equation on non-conservation form (Eqn. \ref{eq:governing:mom:non}).
Now, let's replace the substantial derivative <math>D\mathbf{v}/Dt</math> using the momentum equation on non-conservation form {{EquationNote|label=eq-mom-pde-non-cons}}.


{{NumEqn|<math>
{{NumEqn|<math>
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{{NumEqn|<math>
{{NumEqn|<math>
\rho\frac{De}{Dt} \cancel{-\mathbf{v}\cdot\nabla p} + \cancel{\mathbf{v}\cdot\nabla p} +  p(\nabla\cdot\mathbf{v}) = \dot{q}\rho\Rightarrow \rho\frac{De}{Dt} + p(\nabla\cdot\mathbf{v}) = \dot{q}\rho
\rho\frac{De}{Dt} \cancel{-\mathbf{v}\cdot\nabla p} + \cancel{\mathbf{v}\cdot\nabla p} +  p(\nabla\cdot\mathbf{v}) = \dot{q}\rho\Rightarrow</math><br><br><math>\Rightarrow\rho\frac{De}{Dt} + p(\nabla\cdot\mathbf{v}) = \dot{q}\rho
</math>}}
</math>}}


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{{NumEqn|<math>
{{NumEqn|<math>
\frac{De}{Dt} + \frac{p}{\rho}(\nabla\cdot\mathbf{v}) = \dot{q}
\frac{De}{Dt} + \frac{p}{\rho}(\nabla\cdot\mathbf{v}) = \dot{q}
</math>}}
</math>|label=eq-energy-pde-non-cons-b}}


Conservation of mass gives
Conservation of mass gives
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</math>}}
</math>}}


Insert in Eqn. \ref{eq:governing:energy:non:b}
Insert in {{EquationNote|label=eq-energy-pde-non-cons-b|nopar=1}}


{{NumEqn|<math>
{{NumEqn|<math>
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</math>}}
</math>}}


with <math>De/Dt</math> from Eqn. \ref{eq:governing:energy:non:b}
with <math>De/Dt</math> from {{EquationNote|label=eq-energy-pde-non-cons-b|nopar=1}}


{{NumEqn|<math>
{{NumEqn|<math>
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{{NumEqn|<math>
{{NumEqn|<math>
\frac{Dh}{Dt}=\dot{q} + \frac{1}{\rho}\frac{Dp}{Dt}
\frac{Dh}{Dt}=\dot{q} + \frac{1}{\rho}\frac{Dp}{Dt}
</math>}}
</math>|label=eq-energy-pde-non-cons-c}}


==== Total Enthalpy Formulation ====
==== Total Enthalpy Formulation ====
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</math>}}
</math>}}


From the momentum equation (Eqn. \ref{eq:governing:mom:non})
From the momentum equation {{EquationNote|label=eq-mom-pde-non-cons}}


{{NumEqn|<math>
{{NumEqn|<math>
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</math>}}
</math>}}


Inserting <math>Dh/Dt</math> from Eqn. \ref{eq:governing:energy:non:c} gives
Inserting <math>Dh/Dt</math> from {{EquationNote|label=eq-energy-pde-non-cons-c|nopar=1}} gives


{{NumEqn|<math>
{{NumEqn|<math>
\frac{Dh_o}{Dt}=\dot{q} + \frac{1}{\rho}\frac{Dp}{Dt}+\mathbf{v}\cdot\mathbf{f} -\frac{1}{\rho}\mathbf{v}\cdot\nabla p = \frac{1}{\rho}\left[\frac{Dp}{Dt}-\mathbf{v}\cdot\nabla p\right] + \dot{q} + \mathbf{v}\cdot\mathbf{f}
\frac{Dh_o}{Dt}=\dot{q} + \frac{1}{\rho}\frac{Dp}{Dt}+\mathbf{v}\cdot\mathbf{f} -\frac{1}{\rho}\mathbf{v}\cdot\nabla p =</math><br><br><math>=\frac{1}{\rho}\left[\frac{Dp}{Dt}-\mathbf{v}\cdot\nabla p\right] + \dot{q} + \mathbf{v}\cdot\mathbf{f}
</math>}}
</math>}}